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4k^2+15k=-9
We move all terms to the left:
4k^2+15k-(-9)=0
We add all the numbers together, and all the variables
4k^2+15k+9=0
a = 4; b = 15; c = +9;
Δ = b2-4ac
Δ = 152-4·4·9
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-9}{2*4}=\frac{-24}{8} =-3 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+9}{2*4}=\frac{-6}{8} =-3/4 $
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